Problems on Trains - General Questions
20 Seconds |
8 Seconds |
7.5 seconds |
9 Seconds |
Speed of train in m/s = 120 x 5/18 = 300/18 = 50/3 m/s
Distance covered to cross the platform is equal to the sum of length of the train and length of the platform.
So, distance= 150 + 100 = 250 meters
∵ Time = Distance/Speed
= 250 x 3/100
= 750/100
= 7.5 seconds.
7 seconds |
10 seconds |
8 seconds |
6 seconds |
Time = Distance/Speed
so the relative speed = (speed of train - speed of man)
∵ Relative Speed = (70-10) = 60 km/hr
∵ Relative Speed in m/s = 60 x 5/18 = 300/18 = 50/3 m/s
Distance covered to cross the man = length of the train (100 meters)
Time = Distance/Speed
= 100 x 3/50
= 300/50 = 6 seconds.
57 seconds |
52 seconds |
42 seconds |
55 seconds |
Time = Distance covered/Speed
In this problem, both the trains are in motion so we will find the relative speed of the train. They are moving in the same direction, so the relative speed is equal to the difference of their individual speeds.
∵ Relative Speed: (82-64) = 18 km/hr
∵ Relative Speed in m/s: 18 x 5/18 = 5 seconds.
Distance covered is equal to the sum of the length of trains: 120+140 = 260 meters
Time = 260/5 = 52 seconds.
50 km/hr |
60 km/hr |
55 km/hr |
52 km/hr |
the speed of train relative to man is the sum of their individual speeds.
Let the speed of train is X km/hr
Then the relative speed will be: (X + 10) km/hr
the relative speed is to divide the distance covered (length of train) by the time taken by the train to cross the man.
∵ Relative Speed = 200/12 = 50/3
∵ Relative Speed in Km/hr = 50/3 x 18/5 = 900/15 = 60 km/hr
⟹ Now, X+10 = 60
⟹ X = 60 − 10 = 50 km/hr
61 km/hr |
56 km/hr |
50 km/hr |
54 km/hr |
Speed of the train relative to man = 125/10 m/sec
(25/2) m/sec
( 25/2 x 18/5 ) km/hr
= 45 km/hr.
∵ Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
⟹ x - 5 = 45
⟹ x = 50 km/hr.
≪ 1 2 3 4 5 ≫
0 Comments